How many triangles can<span> you </span>construct<span> given three </span>angle<span> measures whose sum is 180°? The sum of the</span>angle<span> measures of any </span>triangle<span> is 180°. You </span>can<span> use a protractor to </span>construct<span> a </span>triangle<span> given three</span>angle<span> measures. </span>90 90<span>. </span>80<span> 100. 70 110. 60. 120. 50. 130. 40. 140. 30. 150. 20. 160. </span>10. 170. 0. 180. 100.80<span>. 110 70. 12.</span>
Yes because,
8×1 = 8
8×2 = 16
8×3 = 24
8×4 = 32
8×5 = 40
So 40 is a multiple of 8
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
Answer:
these are the step to follow so A=bh
Step-by-step explanation: A=1/2bh A=bh A=1/2 (b=b)h this is an example so you can follow how i did this
Wouldn’t you add both of the equations together and set them equal to 180 and whatever you get for x just plug back in to find the values of the angles??