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Juli2301 [7.4K]
3 years ago
7

What is the approximate value of the correlation coefficient from the given graph

Mathematics
1 answer:
lord [1]3 years ago
6 0
There is no graph given

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James had $200 he wanted to buy a pen which cost $5 how many pens can he buy?
liq [111]
200/5=40
He can buy 40 pens!! 
Hope this helps!! 

3 0
3 years ago
Which similarity statement expresses the relationship between the two triangles?
Dmitry_Shevchenko [17]

<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>

Step-by-step explanation:

∆FGE ~ ∆ JKL

i.e, Angle FGE = angle JKL = 63°

and angle GEF = angle KLJ = 29°

also, angle GFE = angle KJL = 88°

so, the ∆FGE ~ ∆ JKL by AA property of similarity !!

• not other options because if we take corresponding angle they are not equal

For eg. for ∆ EFG ~ ∆ JKL

the angle EFG must be equal to angle JKL to be similar !!

but they are not equal !!

so, they are not similar !!

and such ,all other options except 3rd is wrong !!

7 0
3 years ago
Read 2 more answers
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
3 years ago
university theater sold 465 tickets for a play. ticket cost $23 per adult and $13 per senior citizen. if total receipts were $71
erik [133]

a=adult tickets


s = senior tickets


a+s=465       a = 465-s


23a + 13s = 7145


substitute in a = 465-a


23 (465-s) + 13s = 7145


distrubute


10695 - 23s +13s =7145


combine like terms


10695 - 10s = 7145


subtract 10695 from each side


-10s = -3550


divide by -10


s = 355


senior tickets sold 355



6 0
3 years ago
Are all terminating and repeating decimals rational numbers?
olganol [36]

Answer:

Yes they are rational numbers

Step-by-step explanation:

Rational numbers are Any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions. ... So, any terminating decimal is a rational number.

4 0
3 years ago
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