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WINSTONCH [101]
3 years ago
11

N+4-9-5n help please ill give brainliest

Mathematics
2 answers:
marshall27 [118]3 years ago
6 0

Answer:

-4n - 5

hope this helps! :)

Anna007 [38]3 years ago
6 0
-4n-5 hope this helps you
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A bank offers an annual simple interest rate of 8% on home improvement loans. Tobias borrowed $17,000 over a period of 2 years.
Cerrena [4.2K]
The correct answer is C hope this helps!
3 0
3 years ago
Can someone please explain how to solve this step by step with answer? Thank you.
lidiya [134]

a)

well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.

b)

now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&960\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=years\dotfill &3 \end{cases} \\\\\\ 960=(4000)(r)(3)\implies \cfrac{960}{(4000)(3)}=r\implies 0.08=r \\\\\\ \stackrel{\textit{converting to percentage}}{r=0.08\cdot 100}\implies r=\stackrel{\%}{8}


c)

let's make the rate 1% greater then, and check


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}

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3 years ago
Find the coordinates of the triangle X'Y'Z' after the given transformation
Sergio [31]

Answer:

I need the transformstion lol

7 0
3 years ago
Write a multiplication problem in which the product is between 0.05 and 0.75
RSB [31]
00.57 × 0.75  that willl give you your answer
4 0
3 years ago
Read 2 more answers
(a^2·a^3·(a^−1))^2 <br><br> PLEASE ANSWER
Dovator [93]

\bf (a^2\cdot a^3\cdot a^{-1})^2\implies (a^{2+3-1})^2\implies (a^4)^2\implies a^{4\cdot 2}\implies a^8

4 0
3 years ago
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