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2 years ago

the ferris wheel makes 12 revolutions per ride how far would someone travel during one ride. the diameter is 63 feet

Mathematics

2 answers:

Elan Coil [88]2 years ago

6 0

Using the formula for circumference from diameter (c=pi(d)), we find that the circumference of the ferris wheel is about 197.97 feet. We then multiply that number by the revolutions to get 2,374.64 feet, which is the answer.

NeX [460]2 years ago

4 0

You are actually calculating "arc length." The formula for that is s=r times theta,
where s is the arc length or distance traveled in a circle, and theta is the central angle (always in radians, never in degrees).

Actually, you could obtain the same result by using the formula for circumference of a circle. The distance around the wheel is 2 pi r, where r is the radius and is one half of the given diameter. calculate this circumference / distance, and then multiply your result by 2.

Note that your final answer MUST include units of measurement (of distance).

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3 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

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2 years ago

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Gala2k [10]

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1 year ago

Read 2 more answers

A) Draw the graph of y= 4x - 1 on the grid

UkoKoshka [18]

9514 1404 393

Answer:

see attached for a graph

x = 0.5 when y = 1

Step-by-step explanation:

The graph has a y-intercept of -1, which is halfway between 0 and -2. It goes up 4 units (2 vertical grid spaces) for 1 unit to the right (1 horizontal grid space). It seems to cross y = 1 at about x = 1/2.

x = 1/2 when y = 1.

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2 years ago