The impedance of transformer coil that has 600 feet is 10+j 22.62 Ω (ohms)
Explanation:
It is given that
a #22 copper wire has resistance= R= 10 Ω
inductance= I=0.06 H
N=60 HZ
X= 2π * N * I
=2 * 3.14 * 60 *0.06
X=22.62 Ω
Impedance is calculated by
Z = R + j * X
=10+ j (22.62 Ω)
Z= 10+ j 22.62 Ω
The impedance of a transformer coil that has 600 feet is Z= 10+ j 22.62 Ω
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Hope this answered your question ._.
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