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Alekssandra [29.7K]

3 years ago

5

State the postulate or theorem that proves that the triangles are congruent. If the triangles cannot be proven congruent, write

not possible.

1 answer:

Ivenika [448]3 years ago

8 0

I dont know :(

i actually tried it but im not good with that :)

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(m-3)/(7)=(m)/(m+8) Solve the proportion.

ExtremeBDS [4]

Answer: m=6, m=-4

Step-by-step explanation:

To solve this proportion, we have to cross multiply.

$\frac{m-3}{7} =\frac{m}{m+8}$

$(m-3)(m+8)=7m$

Now that we have cross multiplied, we actually need to FOIL the left side to expand the equation.

$m^2+8m-3m-24=7m$

Combine like terms.

$m^2+5m-24=7m$

We can move all terms to one side and then solve for m.

$m^2-2m-24=0$

We can actually factor this to:

$(m-6)(m+4)=0$

We set each factor equal to 0 to find m.

m-6=0

m=6

m+4=0

m=-4

6 0

3 years ago

√25 + √144<br>who can solve please

Masja [62]

Answer:

17

Step-by-step explanation:

√25 = 5

√144 = 12

5 + 12 = 17

Please mark me Brainliest :)

5 0

3 years ago

Read 2 more answers

A system of equations has no solution. if y=8x+7

Black_prince [1.1K]

And y=8x+c where c≠7
or
8x-y=-c where c≠7

3 0

4 years ago

What is the answer to this question?

AfilCa [17]

The answer should be B.

4 0

4 years ago

Select the correct answer from each drop-down menu.

Oksi-84 [34.3K]

Answer:

$we \: have \: ohms \: law \: h = {i}^{2} rt \\ \frac{h}{t} = {i}^{2} rt \div t = p \\ p = {i}^{2} r....(1) \\ we \: have \: v = ir \\ i = \frac{v}{r} .....(2) \\ put \: (2) \: in \: (1) \\ then \: p = { (\frac{v}{r}) }^{2} r \\ p = \frac{ {v}^{2} }{r} \\ v = \sqrt{pr} = {(pr)}^{ \frac{1}{2} } \\ 2) \\ here \: r = 32 \: and \: p = .5 \\ then \: v = \sqrt{32 \times .5} \\ = \sqrt{16} = 4volt \\ thank \: you$

6 0

3 years ago