Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Answer:
1.918
Step-by-step explanation:
1 then do 459/500 x 2 to make 918/1000 then add and convert
-x+6 ??? im not 100% sure
Answer:
It is the last one or E
Step-by-step explanation:
over 5 down 4 to get the midpoint
then another over 5 down 4 for the endpoint
1/5x + 3 = 10
Subtract by 3 on both sides.
1/5x = 7.
Now to isolate the variable, flip the coefficient in front of the variable and multiply both sides by it.
5(1/5x) = 7(5)
x = 7(5)
x = 35
Now to check:
1/5(35) + 3 = 10
35/5 + 3 = 10
35/5 is 7.
7 + 3 = 10
10 = 10
