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KatRina [158]
3 years ago
9

What is the difference between a quart and a half a gallon

Mathematics
2 answers:
Citrus2011 [14]3 years ago
6 0
A quart is one half of a quart and a half is half of a gallon. A gallon is four quarts.
den301095 [7]3 years ago
3 0
Well 4 quarts is a gallon so if you take half the gallon away then you got 2 quarts so basically every quater of a gallon is a quart =D hope this helped 
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Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?
fgiga [73]
1.0g/cm3 means that the mass of one cm3 is 1.0g
The easiest method to use is the rule of three, and let x be the mass of 10.0 cm3 of water
1g -- > 1.0 cm3
x --> 10.0 cm3

x= (10*1)/1
x=10.0 g

So the mass of 10.0 cm3 of water is 10.0g

Hope this Helps! :)
8 0
4 years ago
Read 2 more answers
If (1 + 2x)^5+ (1 - 2x)^5 = a + bx + cx?<br> find the values of the constants a, b and c.
eimsori [14]

Answer:

steps below

Step-by-step explanation:

5th level of Pascal triangle: 1,5,10,10,5,1

(1+2x)⁵ = 1*1⁵*(2x)⁰+5*1⁴*2x+10*1³*(2x)²+10*1²*(2x)³+5*1¹(2x)⁴+1*1⁰*(2x)⁵

           = 1 + 10x + 40x² + 80x³ + 80x⁴ + 32x⁵   .. (1)

(1-2x)⁵ =  1  - 10x + 40x² - 80x³  + 80x⁴ - 32x⁵  .. (2)

(1)+(2): (1+2x)⁵ + (1-2x)⁵ = 160x⁴ + 80x² +2

a + bx + cx ?? suppose it's ax⁴ + bx² + cx, if you have other set up.. adjust by yourself

<u>a = 160,    b = 80,    c = 2</u>

3 0
3 years ago
How do I know whether something is a function or not? Answer the worksheet please
djyliett [7]
Because you if it changes its a function
6 0
4 years ago
Estimate the quotients 1.64÷22
Nadya [2.5K]

ANSWER

0.1

EXPLANATION

We want to estimate the quotient of 1.64 ÷ 22.

To do this, we will approximate the two numbers to whole number and solve it.

It becomes:

2 ÷ 20

That is:

Note: since 2 cannot be divided by 20, we write 0. and add a 0 to the back of 2.

The estimate of the quotient is 0.1.

3 0
1 year ago
How to factor z²-4z+4
allochka39001 [22]

\implies {\blue {\boxed {\boxed {\purple {\sf { \: ({ \: z - 2 \: })^{2}  \:   }}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

{z}^{2}  - 4z + 4

=  {z}^{2}  - 2z - 2z + 4

Taking "z" as common from first two terms and "2" from last two terms, we have

= z \: ( \: z - 2 \: ) - 2 \: ( \: z - 2 \: )

Taking the factor (z-2) as common,

= ( \: z - 2 \: )( \: z - 2 \: )

=  {( \: z - 2 \: )}^{1 + 1}

=  ({ \: z - 2 \: })^{2}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35❦}}}}}

8 0
3 years ago
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