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3 years ago

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Ian invested $90,000 in an account paying an interest rate of 2.6% compounded quarterly. Assuming no deposits or withdrawals are

made, how much money, to the nearest dollar, would be in the account after 7 years?

1 answer:

barxatty [35]3 years ago

8 0

Answer:

A≈<u>107902</u>

Step-by-step explanation:

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NEED ANSWER ASAP <br> MARKING BRAINLIEST

stepan [7]

Answer:

374.12

Step-by-step explanation:

5 0

3 years ago

Can somone help me with this 1 problem? In the figure shown, △RST is an isosceles triangle with RS≅RT. Which is the measure of ∠

anastassius [24]

In an isosceles triangle, the angles opposite to the two equal sides are also congruent.
Based on your information, T and S are congruent. So we know that the measure of angle T is 3x+7. But we need to solve for x. Let's add all the angle values together and set it to 180 because the angles of a triangle sum to 180.
1) 2(3x+7) + 2x - 2 = 180
2) 6x + 14 + 2x - 2 = 180
3) 8x + 12 = 180
4) 8x = 168
5) x = 21
6) m<T = 3x + 7 = 3(21) + 7 = 63 + 7 = 70
I got C, but it is always helpful to double check work. Hope this helps!

5 0

3 years ago

(7 + 10i)+(4-10i)-(7-5i)

AleksAgata [21]

Answer:

4 + 5i

Step-by-step explanation:

To calculate this you have to combine the like terms until they cannot be combined any further:

7 + 10i + 4 - 10i - (7 - 5i)

11 + 0i - 7 - 5i

7 & 4 are liked terms so add them together + subtract 10i and 10i

4 + 5i <--- Final answer

Hope this helps!

8 0

3 years ago

Read 2 more answers

A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p

Kay [80]

Answer:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by $V= 10 +t$

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

$\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}$

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of $\frac{A}{10+t}$

So then we can reorder the differential equation like this:

$\frac{dA}{dt} +\frac{A}{10+t} =8$

We find the solution using the integration factor:

$\mu = -\int \frac{1}{10+t} dt = -ln(10+t)$

And then the solution would be given by:

$A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})$

And if we simplify this we got:

$A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)$

And after do the integral we got:

$A= \frac{c}{10+t} +4 (10 +t)$

And using the initial condition t=0 A= 20 we have this:

$20 = \frac{c}{10} +40$

$c= -200$

So then we have this function for the solution of A:

$A= \frac{-200}{10+t} +4 (10 +t)$

And now replacinf t= 40 we got:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

8 0

3 years ago

If pn= pn-1 +4 and p17=74, then p3=

MariettaO [177]

Your answer is p3=18

5 0

3 years ago