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Misha Larkins [42]
3 years ago
14

In an upcoming race, the top 3 finishers will be recognized with the same award. Ryan is one of 12 people entered in the race.

Mathematics
2 answers:
BARSIC [14]3 years ago
5 0
Since top 3 racers recognized with the same award, answer is 3/12 or 1/4 or .25
Fiesta28 [93]3 years ago
5 0

Answer:  The required probability is 25%.

Step-by-step explanation:  Given that in an upcoming race, the top 3 finishers will be recognized with the same award and Ryan is one of 12 people entered in the race.

We are to find the probability that Ryan will be one of the top 3 racers, if all racers are equal in skills.

Let S denote the sample space of the experiment for selecting a racer and A denote the event of selecting the top 3 finishers.

Then, according to the given information, we have

n(S) = 12   and    n(A) = 3.

So, the probability of event A is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{12}=\dfrac{1}{4}\times100\%=25\%.

Thus, the required probability is 25%.

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Line segment ON is perpendicular to line segment ML. What is the length of segment NP?
boyakko [2]

Answer:

2 units.

Step-by-step explanation:

In this question we use the Pythagorean theorem which is shown below:

Given that

The right triangle OMP

The hypotenuse i.e OM is the circle radius =5 units.

The segment MP = 4 units length

Therefore

OP^2 + MP^2 = OM^2

OP^2 + 4^2 = 5^2

OP^2 + 16 = 25

So OP is 3

Now as we can see that ON is also circle radius so it would be 5 units

And,

ON = OP + PN

So,

PN is

= ON - OP

= 5 units - 3 units

= 2 units

7 0
3 years ago
Hurry help ASAP!!!!!!!!!!! will give brainliest
Alex17521 [72]
The answer is C. 16 since the 3 first surveys medians are 15,16,16. The median of those 3 numbers is 16. So the answer would be C. 16
5 0
4 years ago
If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each o
Ludmilka [50]

Answer:

16/33

Step-by-step explanation:

12C4(total possible outcomes)=495

Since there are 6 married couples there must be 6*[2C2×10C2]=270

must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255

the no of groupings with no married couples 495-255 =240

probability=no of favourable outcomes /no of possible outcome

probability=240/495= 16/33

6 0
3 years ago
(HELP FINAL EXAM) If two states are selected at random from a group of 40 ​states, determine the number of possible outcomes if
Hitman42 [59]

Answer:

With replacement, there are 1600 possible outcomes.

Without replacement, there are 1560 possible outcomes.

Step-by-step explanation:

Chosen with replacement:

State is chosen, then put back in the group, then another state can be chosen. In both cases, there will be 40 possible outcomes, as the first taken state is placed back. So

40*40 = 1600

With replacement, there are 1600 possible outcomes.

Chosen without replacement:

State and chosen and is not replaced.

So, for the second state, there will be only 39 possible outcomes.

40*39 = 1560

Without replacement, there are 1560 possible outcomes.

7 0
3 years ago
Cabs use a valuable commodity—gas! Research average gas prices from 2005–
Doss [256]

Answer:

a

Step-by-step explanation:


6 0
3 years ago
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