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3 years ago

Instructions: Find the missing side of the triangle. 24 and 7

Mathematics

1 answer:

ANTONII [103]3 years ago

5 0

We can use the Pythagorean theorem to solve this. The Pythagorean theorem is a^2 + b^2 = c^2. We already have a and b, we need to find c. 24^2 + 7^2 is 625. Then, we need to find the square root of 625 to find c. The answer is 25. x = 25.

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Calculus: Help ASAP

Serggg [28]

$\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot dx\\\\
-------------------------------\\\\
u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\$

$\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
\\\\\\
u(0)=4(0)^6+2()\implies u(0)=0\\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4} \right]_{2}^{0}\implies \left. \cfrac{u^4}{8} \right]_{2}^{0}\implies [0]-[2]\implies -2$

5 0

3 years ago

Question12....................................

tatyana61 [14]

Answer:

u = ± 4

Step-by-step explanation:

Given

u² = 16 ( take the square root of both sides )

u = ± $\sqrt{16}$ = ± 4

u = - 4, u = 4

5 0

3 years ago

What is the value of 3 + y ÷ 4, when y = 16?

tankabanditka [31]

Well lets do this

3 + 16 ÷ 4

we divide first

3 + 4

Addition

=7

6 0

3 years ago

A washer and a dryer cost $664 combined. The washer costs $86 less than the dryer. What is the cost of the dryer?

andreyandreev [35.5K]

Answer:

The dryer is 375 dollars

Step-by-step explanation:

The equation would be

664=(D)+(D-86) or

664=(375)+(375-86)

4 0

3 years ago

Limit

STatiana [176]

Rationalize the numerator:

$\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}$

This is continuous at $x=0$ , so we can evaluate the limit directly by substitution:

$\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14$

5 0

3 years ago