Answer:
See below and attached
Step-by-step explanation:
<u>As per the graph we have:</u>
- Coordinates of JL are J(-7, 4), L(-4, 0)
- Coordinates of MP are M(-10, 8), P(-1, -4)
<u>Slope formula is:</u>
<u>Slope of JL:</u>
- (0 - 4)/(-4-(-7)) = - 4 / 3
<u>Slope of MP:</u>
- (-4 -8)/(-1- (-10)) = -12 / 9 = - 4/3
Let 
be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time 
is given by
and its height is
where 
is 9.8 m/s^2, the magnitude of the acceleration due to gravity.
The time it takes for the cat to hit the ground is with
(Unfortunately, this doesn't match any of the given options...)
The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed was
(Again, not one of the answer choices...)
I'm guessing there's either a typo in the question or answers.
Answer:
The first answer is correct.
Step-by-step explanation:
Line 5 says that the reason is due to substitution
Line 3 says m∠ SQT equals 180°
If we substitute 180° into the spot for m∠ SQT in line 4, we get solution option 1
Answer:
Given f(x)=32
So we can substitute 32 in place of 'x'
So, f(x)=3x-1
= f(x)=3(32)-1
= f(x)=96-1
= f(x)=95
f(x)=3x-1 = 95
