Answer:
As with any function, the domain of a quadratic function f(x) is the set of x -values for which the function is defined, and the range is the set of all the output values (values of f ). Quadratic functions generally have the whole real line as their domain: any x is a legitimate input. The vertex will be the minimum (lowest point) of the graph if and the maximum (highest point) of the graph if
Answer:
You are taking away 4 each time
Step-by-step explanation:
25 - 4 = 21
21 - 4 = 17
17 - 4 = 13
13 - 4 = 9
Answer: Both the equations when solved have different answers, the solutions for both the equation are given below. In the the first equation 4 (x-3)=16 , 4 is multiplied with both the terms in the bracket. Whereas, in the second equation 4x- 2 = 16 there is no variable to multiply with the LHS equation
Solution:
4 (x-3)=16
4x - 12 = 16
4x = 16 + 12
4x = 28
x = 7
4x - 3 = 16
4x = 16 + 3
4x = 19
x = 19/4
x = 4.75
Answer:

Step-by-step explanation:
Given


Required
Determine the profit function
This is calculated as follows:

Substitute values for R(x) and C(x)

Open bracket

Collect like terms


Answer: 7) Max: y = 52
8) Min: y = -51
<u>Step-by-step explanation:</u>
The Max/Min is the y-value of the intercept.
- Max is when the a-value is negative.
- Min is when the a-value is positive.
First, find the x-value of the vertex using the Axis of Symmetry formula:
x = -b/2a. Then plug the x-value into the equation to find the y-value.
7) y = -2x² - 16x + 20
↓ ↓ ↓
a= -2 b= -16 c=20

Max: y = -2(-4)² - 16(-4) + 20
= -2(16) + 64 + 20
= -32 + 84
= 52
*********************************************************************************************
7) y = x² + 12x - 15
↓ ↓ ↓
a= 1 b= 12 c= -15

Max: y = (-6)² + 12(-6) - 15
= 36 - 72 - 15
= 36 - 87
= -51