Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Depends on how rich you are
if you are very rich, use meters (or yards)
if you are kinda rich, use feet
if you are average, use centimeters (or inches)
if poor, use milimeters
Answer:
Si, es muy bueno!
Step-by-step explanation:
Answer: SU, TU, ST is the right answer
Step-by-step explanation: In a triangle
The largest side and the largest angle are opposite to each other
The shortest side and the shortest angle are opposite to each other.
So using the above axioms we can observe the triangle.
The largest angle is m∠U = 80° so the side opposite to it is the largest i.e. ST is the largest
The smallest angle is m∠T = 25° so the shortest side is SU
The third side will be the middle side as the angle ∠S is greater than 25° and less than 80°
So the sides in order from least to greatest are: SU, TU, ST
B, x=12 because 140-80=60, 60/5=12
