Question

a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m find the effort applied to balance the load​

Answer 1

The effort applied : 200 N

Further explanation

Equilibrium rotation

$\large {\boxed {\bold {\sum \tau = 0}}$

F₁.d₁-F₂.d₂=0

F₁.d₁=F₂.d₂

F₁=500 N

d₁=0.5 m

d₂=1.75-0.5=1.25 m

$\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N$