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hodyreva [135]
2 years ago
9

Can someone help me on number 5!!!

Mathematics
1 answer:
babunello [35]2 years ago
7 0

f(x).g(x)

(2x-1).(3)

answer: 6x-3

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Plsssssssss help!!!!!!!!!!!!!!!!!
ss7ja [257]

Answer:

C) ∠LMO = 50°

Step-by-step explanation:

When you add the degrees of all the angles in a triangle, you get 180, so...

180 = 60 + 70 + x

180 - 60 - 70 = x

x = 50

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Christopher had 3 1/2 pies left over from the party. He qually divided the 3 and 1/2 pies between 4 of his friends. How much did
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The answer is 3/8. Christopher with have to share 3/8 of pie with each of his friends.
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Hint: Plug each number into the formula a^2 + b^2 = c^2. Then see which set of numbers balances out.
Anni [7]

Answer:

A

Step-by-step:

a^2+ b^2 = c^2

if we try A

6^2+8^2 = 10^2 => 64+36  = 100

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2 years ago
Eve plays basketball. She makes 7 free throws for every 3 free throws that she misses. If she missed 24 free throws at her last
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3 years ago
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When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in i
Westkost [7]

Answer:

(1) 256 inches

(2) 5 feet

(3) 400 inches

(4) 10 feet

Step-by-step explanation:

(1) The function that gives the height in inches of the spray of water at a distance <em>x</em> from the sprinkler head is given as follows;

h(x) = 160·x - 16·x²

At x = 2 feet, we have;

h(2) = 160 × 2 - 16 × 2² = 256

Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches

(2) The x-coordinate, x_{max}, of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;

x_{max} = -b/(2·a)

The x-coordinate, x_{max}, of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;

x_{max} = -160/(2 × (-16)) = 5

Therefore, the number of feet along the way, the function will reach maximum height, x_{max} = 5 feet

(3) The function, h(x) = 160·x - 16·x², will reach maximum height, h_{max}, at x = 5, therefore;

h_{max} =  h(5) = 160 × 5 - 16 × 5² = 400

The maximum height of the spray, h_{max} = 400 inches

(4) The water is at ground level where h(x) = 0, therefore;

At ground level, h(x) = 0 = 160·x - 16·x²

160·x - 16·x² = 0

∴ 16·x × (10 - x) = 0

By zero product rule, we 16·x = 0, or (10 - x)  = 0, from which we have;

x = 0, or x = 10

The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.

7 0
3 years ago
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