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Anna [14]
3 years ago
14

Steve determined the number of states each of his friends has visited. A number line goes from 0 to 44. The whiskers range from

1 to 40, and the box ranges from 4 to 10. A line divides the box at 8. Which statement must be true according to the box plot?
A. The data is skewed left and shows that half of Steve’s friends have visited 4 to 10 states.
B. The data is skewed left and shows that half of Steve’s friends have visited 10 to 40 states.
C. The data is skewed right and shows that half of Steve’s friends have visited 4 to 10 states.
D. The data is skewed right and shows that half of Steve’s friends have visited 10 to 40 states.
Mathematics
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

The answer is C.

Step-by-step explanation:

Because I just took the test

Mnenie [13.5K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

I got it right on edge

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Simplify the following expression. *<br> 3(x-4)
damaskus [11]

Answer:

3x-12

Step-by-step explanation:

3(x-4)

Distribute

3x -3*4

3x-12

6 0
4 years ago
Write an equation in point-slope form and slope- intercept form for the line.
MAXImum [283]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
I desperately need help​
Naya [18.7K]

Answ you need to find the slope using the coordinates. Then, you need to write the equation in Point-slope form and Slope-Intercept. (If ur teacher wants Standard Form do that too

Step-by-step explanation:

8 0
3 years ago
Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu
True [87]

Answer:

The fraction of the students who failed to went partying = \frac{1}{10}

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = \frac{20}{100} × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = \frac{20}{2} = 10

Thus the fraction of the students who failed to went partying = \frac{10}{100} = \frac{1}{10}

8 0
3 years ago
Please help me!!!!!!!!!!!!!!?
OLEGan [10]
So what you want to do for all of these is move the variable that you want to be the subject to one side of the equation and the other ones to the other side, then divide.

For example:

With number 1, m = 3n + 2p, since you want to make p the subject, first single out p by subtracting 3n from both sides.

m - 3n= 3n + 2p - 3n

2p = m - 3n

Then divide everything by 2.

2p / 2 = m/2 - 3n/2

p = , you could also say 1/2m - 3/2n

p = 1/2m - 3/2n

Next question: just do the same thing.

a = 3c - 4

a + 4 = 3c - 4 + 4

3c = a + 4

/3      /3   /3

c = 1/3a + 4/3

Next question: same process.

P - 2a = 2a - 2a + 2b

2b = P - 2a

/2     /2    /2

b = 1/2P - a
5 0
3 years ago
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