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2 years ago

What is the slope of the line shown below? 1 O A 3 O B. -3 O C. 3 O D.

Mathematics

1 answer:

adell [148]2 years ago

8 0

Answer:

c 3

Step-by-step explanation:

put the rise (change in y) over run (change in x)

find the difference between the y points: 2 and 8

8 minus 2 is 6, so that's your rise

then find the difference between your x points: 2 and 4

4 minus 2 is 2, so that's your run

rise / run = 6/2, which simplified is just 3

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In 2014 Rose invested $16,000 in a savings account for her newborn son. The account pays 3.6% interest each year. Determine the

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Answer:

Total value of the account in 2032 will be $26,368

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2 years ago

Which image shows the correct position of -2 1/2on the number line?

ohaa [14]

The answer to your question would be 'A'

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3 years ago

Trapezoid CDEF is congruent to trapezoid TORS. If CF and DE are parallel, which pair of sides in trapezoid TQRS MUST also be par

kondaur [170]

Answer:

Step-by-step explanation:

TS and QR Is your answer

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3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago

PLEASE HELP!!!!! Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance t

Sveta_85 [38]

Answer:

The answer to your question is Advance = $35 and same-day = $40

Step-by-step explanation:

Advanced = a

Same-day = s

Equations

a + s = 75 ----- (I)

20a + 35s = 2100 ----- (II)

Process

1.- Solve the equations by elimination.

Multiply equation I by -20

-20a - 20s = -1500

20a + 35s = 2100

Simplify

0 + 15s = 600

Solve for s s = 600/15

s = $ 40

Substitute "s" in equation I to find "a"

a + 40 = 75

Solve for a

a = 75 - 40

a = 35

3 0

2 years ago