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Paladinen [302]
3 years ago
15

A rectangular prism and a square pyramid were joined to form a composite figure. A rectangular prism with a length of 9 inches,

width of 9 inches, and height of 5 inches. A square pyramid with triangular sides with a base of 9 inches and height 4 inches. [Not drawn to Scale] What is the surface area of the figure? 261 in.2 333 in.2 405 in.2 477 in.2
Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

I need this to but i think the awnser is B

Step-by-step explanation:

klio [65]3 years ago
6 0

Answer:

The answer is D 477 in.2

Step-by-step explanation:

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The water level at a local pier rises and falls with the tide. Yesterday, the maximum depth of the water at the pier was 8 feet,
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Step-by-step explanation:

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The sum of two numbers is 32 and their difference is 8 what are the two numbers
Likurg_2 [28]
A+b=32
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let's subtract bottom equation from the top:

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3 years ago
(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\

= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\

=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\

= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\
= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\


I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\
I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\


b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\
= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\
= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\






\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\
= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\







c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\

I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\
= \dfrac{2n}{2n+1} * I_{2n-1} \\
= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\
= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\

I_1=1\\






3 0
4 years ago
Find the value of 7C7
Artyom0805 [142]

Step-by-step explanation:

If there were 7 items, the number of ways to choose 7 out of the 7 items is only 1 way, which is to get all of them.

=> 7C7 = 1.

5 0
3 years ago
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