Solve by factoring X^2-100=0
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The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.
<h3>What is the mean of a distribution?</h3>The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.
From the parameters given:
Low-temperature Frequency
40 - 44 2
45 - 49 5
50 - 54 9
55 - 59 6
60 - 64 3
The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.
The class midpoint of 40 - 44 is
The class midpoint of 45 - 49 is
The class midpoint of 50 - 54 is
The class midpoint of 55 - 59 is
The class midpoint of 60 - 64 is
Now, the table can be represented as:
Low-temperature Frequency x
40 - 44 2 42
45 - 49 5 47
50 - 54 9 52
55 - 59 6 57
60 - 64 3 62
The mean can now be determined as follows:
Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F
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