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fiasKO [112]
3 years ago
13

If f(x) = x2+x, find f(- 3)=0-12036​

Mathematics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

-24

Step-by-step explanation:

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Weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. Find the probabi
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Answer:

$80

Step-by-step explanation:

400÷50= 80 which is the weekly rate of wages

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The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
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Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

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3 years ago
Is y=4/6-2x a linear expression
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Step-by-step explanation:

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So paid160


75 percent off
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'of' means multiply
remember tha tpercent is parts out of 100 so
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The answer to this problem is 6.28.
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