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Stels [109]
3 years ago
10

What will be a fundamental aspect of future games?

Computers and Technology
2 answers:
padilas [110]3 years ago
6 0
D. product- oriented :))
horrorfan [7]3 years ago
6 0

Answer:

The correct answer is C

Explanation:

I took the test and it is correct

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In the EXPLORE online library, the ratio of the number of novels to that of dictionaries is 2:3 and the total number of novels i
bonufazy [111]

Answer:

Answer is 2184

Explanation:

1st of all we need to know the total number of novels in the library if I have it with a ratio of one meaning:

2---------624

1----------???

(1×624)÷2 =312

Meaning with a ratio of 1 I'll have 312

Take the 312 and multiply with 7

It will give you 2184

That's the number of Novels which were bought by joe

3 0
2 years ago
2:3:5<br>_ _ _<br>3 2 8<br><br><br><br>find ratio​
TiliK225 [7]

Answer:

453 over 328

Explanation:

I'm just guessing

4 0
3 years ago
One lap around a standard high-school running track is exactly 0.25 miles. Write a program that takes a number of miles as input
WINSTONCH [101]

Answer:

F(x) = x*.25

Explanation:

the amount of miles (x) divided by 4 (four quarters in a mile) or just multiply by .25

6 0
3 years ago
Read 2 more answers
A tool that is used to search for and gather data from a page on the internet is called a ?
pshichka [43]
It is called a sesrc engine
8 0
3 years ago
Read 2 more answers
You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0
3 years ago
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