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expeople1 [14]
3 years ago
6

Assume that the 100,000 element integer array that you allocated starts at address 0x50000000 in memory, the size of an integer

is 4 bytes and the D-cache is initially empty. As you read the integers in the array one-by-one, starting at index 0, how many D-cache misses will you see for reading the first 40 integers when the cache block size is (to be answered without running pin):a) 4 bytes:b) 32 bytes:c) 64 bytes:
Computers and Technology
1 answer:
Vanyuwa [196]3 years ago
6 0

Answer:

40, 5 and 3

See explaination for the details

Explanation:

A)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =4bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/4

= 160/4

= 40

b)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =32bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/32

= 160/32

= 5

c)

Consider the data.

Assume D-cache is empty

An integer size =4bytes

The cache block size =64bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40×4)/64

= 160/64

= 3

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Nutka1998 [239]

Answer:

Here the code is by using java.

Explanation:

//Randomizer.java

public class Randomizer {

public static int nextInt() {

//get random number from 1-10

int randInteger = (int) (Math.random() * (11) + 1);

//if number is greater than 10 or less than 1

while (randInteger > 10 || randInteger < 1) {

randInteger = (int) (Math.random() * (11) + 1);

}

return randInteger;

}

public static int nextInt(int min, int max) {

//formula to get random number from min-max

int randInteger = (int) (Math.random() * (max + 1) + min);

while (randInteger > max || randInteger < min) {

randInteger = (int) (Math.random() * (max + 1) + min);

}

return randInteger;

}

}

//RandomizerTester.java

public class RandomizerTester {

public static void main(String[] args) {

System.out.println("Results of Randommizer.nextInt()");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt());

}

int min = 5;

int max = 10;

System.out.println("\n Results of Randomizer.nextInt(5,10)");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt(min, max));

}

}

}

OUTPUT:

Results of Randommizer.nextInt()

9

2

3

8

5

9

4

1

9

2

Results of Randomizer.nextInt(5,10)

9

8

9

7

5

10

5

10

7

7

4 0
2 years ago
What is output? Select all that apply. c = 0 while (c &lt; 10): c = c + 5 print (c) 0 1 2 3 4 5 6 7 8 9 10
Harlamova29_29 [7]

Answer:

5 10

Explanation:

that's the answer : 5 10

4 0
3 years ago
Mechanisms that combine memory, processing speed, and knowledge to regulate the analysis and flow of information within the info
gizmo_the_mogwai [7]

Answer:

control processes.

Explanation:

Mechanisms that combine memory, processing speed, and knowledge to regulate the analysis and flow of information within the information-processing system are referred to as executive/control processes.

3 0
3 years ago
Light travels at 3 × 108 meters per second. A light-year is the distance a light beam travels in one year.Write a PYTHON program
Volgvan

Answer: This is a python code

def lightyear():

   rate=3*100000000   //speed of light

   seconds=365*24*60*60   //number of seconds in 1 year

   return str((rate*seconds)/1000)+" km"    //distance=speed x time

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OUTPUT :

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Explanation:

In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.

4 0
3 years ago
Five advantages of Internet​
Novosadov [1.4K]

Answer:

Information, knowledge, and learning.

Selling and making money.

Banking, bills, and shopping.

Donations and funding

Entertainment.

Explanation:

I hope this helps! ^^

☁️☁️☁️☁️☁️☁️☁️

7 0
2 years ago
Read 2 more answers
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