Question

Simplify 9xºy-3 Write your answer using only positive exponents.

Answer 1

Answer:

we conclude that:

$\:9x^0y^{-3}=\frac{9}{y^3}$

Step-by-step explanation:

Given the expression

$9x^0y^{-3}$

Apply exponent rule:    $a^{-b}=\frac{1}{a^b}$

$\:9x^0y^{-3}=9\cdot \:\frac{1}{y^3}x^0$

Apply rule:   $a^0=1,\:a\ne \:0$

             $=9\cdot \:1\cdot \frac{1}{y^3}$

Multiply fractions:   $a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

              $=1\cdot \frac{1\cdot \:9}{y^3}$

Refine

               $=\frac{9}{y^3}$

Thus, we conclude that:

$\:9x^0y^{-3}=\frac{9}{y^3}$