Write this as the sum of:
a+md
a+md+d
a+md+d+d
...
a+md+d+d+...+d
Total=n(a+md)+d(1+2+3+...+n-1)=n(a+md)+dn(n-1)/2
Hello!Your answer is

If you use a calculator and divide 23 by 99, you will get 0.232323............
Answer ⇒
4Step-by-step explanation:
Answer:
I do not see the model, but based on what you are telling me, I believe that both the fractions are equal is what is being shown. They are, in other words, equivalent fractions