Answer:
x = 3
, y = 5
Step-by-step explanation:
Solve the following system:
{3 y - 7 x = -6 | (equation 1)
3 y - 3 x = 6 | (equation 2)
Subtract 3/7 × (equation 1) from equation 2:
{-(7 x) + 3 y = -6 | (equation 1)
0 x+(12 y)/7 = 60/7 | (equation 2)
Multiply equation 2 by 7/12:
{-(7 x) + 3 y = -6 | (equation 1)
0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{-(7 x)+0 y = -21 | (equation 1)
0 x+y = 5 | (equation 2)
Divide equation 1 by -7:
{x+0 y = 3 | (equation 1)
0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 3
, y = 5
Answer:
<em>Hey mate, here's ur answer:</em>
<em>---------------------------------------------------</em>
<em>-2x^5. 4x^2 </em>
<em>=(−2)*x5*4*x2
</em>
<em>=−8*x7
</em>
<u><em>=−8x7</em></u>
<em>--------------------------------------------------</em>
<em>Hope it helps</em>
<em>#stayhomestaysafemate</em>
<em>:D</em>
Answer: 78
Step-by-step explanation:
First, we want to find the area of the outer triangles. Remember that the equation to finding the area of a triangle is (l x h) x 1/2. So, let’s substitute the values into the equation. It’ll be (6 x 7) x 1/2. Let’s solve! 6 x 7 = 42. Then, 42 x 1/2 = 21. But let’s not forget that we only found the area of one triangle. We still need to find the area of the other outer triangles. So, to do this, we take 21 and multiply by 3 since the other outer triangles have the same dimensions. We would get 63 as our total area for the outer triangles.
Next, we need to find the area for the inner triangle. We will use the same equation: (l x h) x 1/2. Let’s substitute! (6 x 5) x 1/2 will be our final equation. Now, let’s solve. 6 x 5 = 30. 30 x 1/2 = 15. So, as a process of elimination, our area for the inner triangle is 15.
Finally, we need to add the total areas we found together. Our total areas were 63 and 15. Let’s put this into an equation: 63 + 15 = ?. So, 63 + 15 = 78. So, after a long process, 15 is our answer!
Hope this helped!
Answer:
Since we know that AD =12
AC=1/2*AD
AC=6
AB=BC=1/2*AC
AB=BC=3
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