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Mathematics

1 answer:

Marrrta [24]3 years ago

3 0

Answer:

the answer is around 872

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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

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3 years ago

Find the measure of angle 6 Measure of angle 7=2x+15 measure of angle 8=3x

dedylja [7]

7=2x + 15 2x= -8 x= -4

<span>8= 3x 8= 3x+0 3x +-8 3(-4) +-8 -12 - 8 </span>

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BabaBlast [244]

Hello from MrBillDoesMath!

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