1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
U count how many students were walking then multiply it by half itself
The answer is 5
9+6 = 15
15/3 is 5
Answer:
Step-by-step explanation:
Given
Liam deposited 
Rate of interest is 
If the amount after t years is 
Simple interest is given by

And amount is


Substituting values we get





Answer: 
Step-by-step explanation:
We know that the total number of outcomes for fair dice {1,2,3,4,5,6} = 6
Given : Favorable outcome = 5
i.e. Number of favorable outcomes =1
We know that the formula to find the probability for each event is given by :-

Then, the probability that the six faces cube will land with the number 5 face up will be :_

Hence, the required probability = 