Answer:
Due to the higher Z-score, Demetria should be offered the job.
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
In this question:
Whichever applicant had grade with the highest z-score should be offered the job.
Demetria got a score of 85.1; this version has a mean of 61.1 and a standard deviation of 12.
For Demetria, we have
. So



Vincent got a score of 299.2; this version has a mean of 264 and a standard deviation of 22.
For Vincent, we have
.



Tobias got a score of 7.26; this version has a mean of 7.1 and a standard deviation of 0.4.
For Tobias, we have
.



Due to the higher Z-score, Demetria should be offered the job.
-10x -120-11x
combine like terms so -10-11= -21x-120
The amount of drinks is a linear function of the number of drinks. The maximum amount that can be purchased is 100 soft drinks.
Let
amount of drinks
number of drinks
For drinks not more than 50

For drinks more than 50.

For a purchase of $85, it means that:

So, we solve for x in both equations.


Collect like terms


Divide through by 0.8

--- approximated


Collect like terms


Divide by 0.7

By comparing both values:



Hence, the maximum amount that can be purchased is 100
Read more about functions at:
brainly.com/question/20286983
Answer:
This is a geometric progresion that begins with 1 and each term is 1/3 the preceeding term
Let Pn represent the nth term in the sequence
Then Pn = (1/3)^n-1
From this P14 = (1/3)^13 = 1/1594323
5. The sum of the first n terms of a GP beginning a with ratio r is given by
Sn = a* (r^n+1 - 1)/(r - 1)
With n = 10, a = 1 and r = 1/3, S10 = ((1/3)^11 - 1)/(1/3 - 1) = 1.500