Answer: y=2/5x
Step-by-step explanation:
Y times x 2/5 which would be the answer
Ok so you would plug in 18 for the x so it would be 6(18)-12 and then 6x18 is 108 and 108-12=96 so your answer is 96
Answer:
see explanation
Step-by-step explanation:
A
Given
(x² + 3)² + 21 = 10x² + 30 ← factor out 10 from each term on the right side
(x² + 3)² + 21 = 10(x² + 3) ← subtract 10(x² + 3) from both sides
(x² + 3)² - 10(x² + 3) + 21 = 0
Substituting u = x² + 3 into the equation gives
u² - 10u + 21 = 0 → D
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B
Using u² - 10u + 21 = 0 to solve the equation
Consider the factors of the constant term (+ 21) which sum to give the coefficient of the u- term (- 10)
The factors are - 3 and - 7, since
- 3 × - 7 = 21 and - 3 - 7 = - 10, thus
(u - 3)(u - 7) = 0
Equate each factor to zero and solve for u
u - 3 = 0 ⇒ u = 3
u - 7 = 0 ⇒ u = 7
We now have to use the substitution to convert the solutions into terms of x, that is
x² + 3 = 3 ( subtract 3 from both sides )
x² = 0 ⇒ x = 0 → D
x² + 3 = 7 ( subtract 3 from both sides )
x² = 4 ( take the square root of both sides )
x = ±
= ± 2
Thus x = - 2 → C
x = 2 → E
The factor of 52 is 1, 2, 4, 13, 26, and 52
If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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