Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3
Answer:
3 1/6
Step-by-step explanation:
2 1/2 + 2/3 = 2 3/6 + 4/6. add 3 and 4, you get 2 7/6. simplify by taking 6 from 7 and add 1 to 2. that leaves you with the answer
B)
here,
A to B = 62
C To B = 11
A to C = ?
now,
so, 62 - 11 = 51
therefore a to C Is 51 cm
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A)
Here,
A to B = 13
A to C = 26
total = ?
now,
A to B + A to C
13 + 26 = 39
Therefore,
total number is 39
Answer:
32
Step-by-step explanation:
We can write an algebraic equation to solve this situation: 
, where x = first integer (small number) and x + 1 = the following integer.
Step 1: Combine like terms.
Step 2: Subtract 1 from both sides.
Step 3: Divide both sides by 2.
Therefore, the smaller number is 32 while the larger number is 33.
Have a lovely rest of your day/night, and good luck with your assignments! ♡
Answer:
(-3,-9)
Step-by-step explanation:
