3 years ago

Please HELP ASAPAPPPP!!?!!??

Mathematics

1 answer:

NISA [10]3 years ago

7 0

Answer:

36 - 18 longest side = 18

Step-by-step explanation: This would mean both sides are 18.

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puteri [66]

Yes they are all right

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3 years ago

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pishuonlain [190]

A)
= 3 2/4
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b)
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3 years ago

Use the quadratic formula to solve 2x^2=5x+6. Leave your answer in radical form. Show all of your work!

Westkost [7]

Answer:

In radical from 169/50 , 177/200

Step-by-step explanation:

Given:

$2x^2=5x+6\\\\2x^2-5x-6=0\\\\Where, a=2 , b=-5 , c=-6$

Find:

Value of $x$

Computation:

Using quadratic formula:

$\frac{-b\±\sqrt{b^2-4ac} }{2a}\\\\By\ putting\ all\ value\\\\ \frac{-(-5)\±\sqrt{(-5)^2-4(2)(-6)} }{2(2)}\\\\ \frac{5\±\sqrt{25+48} }{4}\\\\ \frac{5\±8.54 }{4}\\\\\frac{5+8.54 }{4},\frac{5-8.54 }{4} \\\\3.38 , 0.885$

Value of $x$ 3.38 , 0.885

In radical from 169/50 , 177/200

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3 years ago

Find two consecutive even integers such that the sum of the larger and twice the smaller is 62

kolbaska11 [484]

20 and 22

You would create an equation that would simulate this situation and solve for x to find the first even integer. Then add 2 to x to find the second even integer.

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If 8 identical blackboards are to be divided among 4 schools, how many divisions are possible? how many if each school must rece

DaniilM [7]

Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then

( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165

For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35

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3 years ago