Answer: I got the answer by adding and subtracting
Step-by-step explanation:
Answer:
m∠N = 32°
NQ = 106°
When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.
<span>3a^2+12a = 3a(a+4)
...</span>
Answer:
The iron weighed 1/12 pound more than the aluminum.
Step-by-step explanation:
The weight of the aluminum is given as 1/2 pound. But that can also be written as 6/12 pound.
This is a subtraction problem (subtracting fractions...so also a common denominator problem)
In order to subtract fractions you have to get a common denominator.
7/12 - 1/2
= 7/12 - 6/12
= 1/12
The iron is 1/12 pound heavier than the aluminum.
Are there any multiple choice answers?
