Answer: 26
Step-by-step explanation:
divide 19.5 by 3/4 (0.75)
Answer:
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Step-by-step explanation:
7 + 13 = 20
13 + 7 = 20
13 – 13 = 0
13 – 0 = 13
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Answer:
Less than
Step-by-step explanation:
Although it wasn't an option, it is less than. In order to accurately compare then, you have to get the least common denominator. Using the least common multiple (2), you multiply 5/8 by 2 and end up with 10/16. Now 10 is less than 11, so the option is neither of those. 5/8 is less than 11/16.
Problem One
Remark
If she doesn't mind having I kg left over, the minimum number would be 3 five kg boxes. If on the other hand, she must have exactly 14 kg then the minimum number is 6.
She needs 2 five kg boxes and 4 one kg boxes. <<<< Answer
Problem Two
There is a method of solving this that is called dimensional analysis. It is what should be used here. I'll do it at the end of the problem. In the meantime, you have to do it a slightly longer way.
1 portion = 100 grams.
x portions = 1kg which is 1000 grams.
x portions = 1000 grams.
Set up a proportion to find the number of servings in 1 kg
1 portion/x = 100 grams/1000 grams Cross multiply
1 * 1000 = 100 * x Divide by 100
1000/100 = x
x = 10 servings in 1 kg.
So each kg produces 10 portions
1 kg / 10 portions = 20 kg / x portions Cross multiply
x * 1 = 10 * 20
x = 200 portions <<<<< Answer
Dimensional Analysis
[1batch]*[1 portion/100g][1000g/kg][20kg/batch] the units cancel
1000 * 20 / 100 only the portions are left over.
200 portions is the answer.
Problem Three
1 kg = 1000 grams
x kg = 5000 grams Cross multiply
1*5000 = 1000 x
x = 5 kg
1 parcel weighs 5 kg
x = 15 kg
15 kg = 5 x
x = 15/5
x = 3
So he can carry 3 parcels per trip.
Since there are 5 such parcels, he will have to make 2 trips. The second one will not be a full load.
First Trip = 3 parcels
Second Trip = 2 parcels. <<<<Answer
