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Kazeer [188]
2 years ago
6

Select all polynomials that have (x-3) as a factor.

Mathematics
1 answer:
Alchen [17]2 years ago
8 0

Answer:

Below.

Step-by-step explanation:

Substitute x = 3 into each polynomial and see if the value of the polynomial is zero. If it is zero then x-3 is a factor.

Try number 1:

a(x) = x^3 - 2x^2 - 4x + 3

a(3) = 3^3 - 2(3)^2 - 4(3) + 3

= 27 - 2(9) - 12 + 3

= 27 - 18 - 12 + 3

= 9 - 18 - 9

= 27 - 27

= 0

So a(x) has (x-3) is a factor of a(x)

The other 3 polynomials are solved in the same way.

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Write each fraction as a sum or difference 14-6x/19
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<span>Given number : 14 - 6x / 19
So we need to write this fraction as a sum or difference.
First, simplify the given number:
=> 14 – 6x / 19
=> <u>14 x 19 – (6x</u>)
            19
=> <u>266 – 6x</u>
         19
=> 266 – 6x = -2 * (3x - 133)
Thus, the final result would be:
=> <u>-2 * (3x - 133) </u> => This will be the fraction sum or difference of the given number<u>
</u>               19

</span>



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