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2 years ago

CAN SOMEONE HELP ME WITH MY TEST

Mathematics

1 answer:

irakobra [83]2 years ago

4 0

The picture isn’t showing up :/

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Pls for the love of god someone explain how to do this to me

viva [34]

I’m not sure...but I think

x+y=5
If x =15
Then 15+y=5
Y= 10
The 2nd robot can do the task in 10min

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2 years ago

Question ^^^^^^^^^^^^^^^^6

hichkok12 [17]

Answer:

Step-by-step explanation:

x+14=x14

4 0

2 years ago

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Select the answer with the correct number of significant figures for each calculation. (6.022 × 10^23) × 2.58 = 1.55 × 10^24 1.5

maxonik [38]

Answer:

1.55 × 10^24

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Use the vertex formula to find the vertex of the quadratic function f(x) = -x2 + 4x - 8.

Irina18 [472]

The vertex of f(x)=-x2+4x-8 is (2, -4)

8 0

2 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

3 years ago