The value of f(4) and 3[f(t)] if f(t) = 2t³ is 512 and 6t³ respectively.
<h3>What is polynomia?</h3>
To calculate the polynomial expression below, we use the technique below.
From the question,
Given:
- f(t) = 2t³.............. Equation 1
To find f(4) we substitute 4 as the value of x in equation 1
To find 3[f(t)] we multiply equation 1 by 3
Hence, the value of f(4) and 3[f(t)] if f(t) = 2t³ is 512 and 6t³ respectively.
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Area is 5 1/4 in ^2 or 5.25 in^2
Workup in picture below
Good luck
Median = n+1/2
number of elements = 11
11+1/2
12/2
6
45 is in the 6th position
First quartile
n+1/2
n=5
6/2
3rd position
37 is in the third position
Third quartile
n+1/2
n=5
6/2
3rd position
44 is the the third position
The interquartile range is Quartile 3 - Quartile 1
44-37
7
20 and 70 are outliers
Find number summary
26 37 45 44 70
Answer:
Domain (-∞,∞). Range= f(x) >-5
Step-by-step explanation:
1) Since we are dealing with a polynomial function with no algebraic restrictions, no denominators, no variables at the exponents, no square roots, etc. And it is a continuous function the Domain is the whole Real Line the Real set of Numbers.
2) As the Range, we have to deal with the combined inverse of this polynomial function.
Do the inversion
Then susbtitute u²= and u=y² back substitute then solve
Jus like this
Back substitute and then solve it for y:
y²=x+
Then y>-5 R=(-5,∞)
https://socratic.org/questions/the-ratio-of-boys-to-girls-at-a-college-is-4-5-how-many-boys-and-are-there-if-th