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3 years ago

A gardener uses 1/3 of a litter of water to water 2/7 of a garden. How much will the garden require?

Mathematics

1 answer:

vfiekz [6]3 years ago

3 0

Answer:

A gardener uses 1/3 of a liter of water to water 2/7 of a garden. Watering the entire garden at this rate will require liters of water.

Step-by-step explanation:

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Lubov Fominskaja [6]

Answer:

It is not

Step-by-step explanation:

It is not because this is an exponential function

y=x^2

1^2=1

2^2=4

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2 years ago

The number 10^100 is called a googol. What kind of number is a googol? Select all correct answers.

lana66690 [7]

Answer: a, b, c, d

Step-by-step explanation: its not a fraction, its a integer, its positive, and is rational (every integer is rational).

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3 years ago

Find the volume of the solid. The volume of the solid is ____ cubic centimeters

Illusion [34]

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2 years ago

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2 years ago

Read 2 more answers

The phenomenon of bottle flipping has hit the nation. You design a machine that can randomly flip a bottle. You observe 2180 ran

krek1111 [17]

Answer:

The variable of interest is the proportion of flips that land the correct way when flipped randomly.

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

Step-by-step explanation:

Variable of Interest:

Proportion of flips that land the correct way when flipped randomly.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Necessary conditions:

The necessary conditions are:

$n\pi \geq 10$

$n(1-\pi) \geq 10$

You observe 2180 random, independent flips, and 325 land the correct way.

This means that $n = 2180, \pi = \frac{325}{2180} = 0.149$

Necessary conditions

$n\pi = 2180*0.149 = 325 \geq 10$

$n(1-\pi) = 2180*0.851 = 1855 \geq 10$

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.33$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.131$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 + 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.167$

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

8 0

3 years ago