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Tpy6a [65]
3 years ago
14

Pleaseeeee help thanks

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

1 freedom of speech

2 bear arms mean that i can own and carry a gun to protect me, myself and my property.

3 search warent

4 the tar and feather used on blacks.

5 fouth

6 it is passed down to mayors

7 i think that the most important amendment is the first because it allows us say what we like without getting punished by it.

sorry bout my bad grammer

Step-by-step explanation:

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Why do you sometimes need to regroup in 3 digit addition problems
SCORPION-xisa [38]
Because for example 349+567 is something you need to regroup.You start by the ones.9+7=16. You don't always need to regroup though
6 0
3 years ago
The ratio of computers to calculators is 59. Find the number of computers if the there are 108 calculators​
MissTica

Answer:

6,372

Step-by-step explanation:

The ratio is 59:1, meaning the new ratio is ?:108

To find the value you're searching for, multiply 108 by 59

108*59=6,372

To check your work you can divide both sides by 108 and if it is correct you should get the ratio 59:1, let's see

6,372/108=59

108/108=1

59:1... we have the right answer!

I hope i helped :)

8 0
4 years ago
How do you find the length of an equilateral triangle with the area?
max2010maxim [7]
Formula used for an equilateral triangle is
Root3 a^2/4
Hope this helps.!!
7 0
3 years ago
A walkway forms one diagonal of a square playground. The walkway is 22 m long. How long is a side of the​ playground?
nadya68 [22]
You can think of a square as two isosceles right angle triangles and use Pythagoras.

x^2 + x^2 = 22^2
x^2 + x^2 = 484
2x^2 = 484
x^2 = 242
x = 11√2

One side of the playground is 11√2 m long.
5 0
4 years ago
The drama club was selling ticketsto the school play. Adult ticketscost $8.00 each, and studenttickets cost $5.00 each. The litt
BlackZzzverrR [31]

We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

A+S=284,(1)

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

8A+5S=1948,(2)

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

\begin{gathered} A+S-S=284-S \\ A=284-S \end{gathered}

Now we will replace this value in equation (2):

8(284-S)+5S=1948

Now we will apply the distributive property:

2272-8S+5S=1948

Addins like terms:

2272-3S=1948

Subtracting 2272 to both sides;

\begin{gathered} 2272-2272-3S=1948-2272 \\ -3S=-324 \end{gathered}

Dividing both sides by -3:

S=-\frac{324}{-3}=108

Now we replace this value in equation (1), where we have already solved for A:

\begin{gathered} A=248-108 \\ A=140 \end{gathered}

Therefore, there were sold 108 student tickets and 140 adult tickets.

3 0
1 year ago
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