9514 1404 393
Answer:
   $7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
   p + d + q = 45 . . . . . . . . there are 45 coins in the collection
   2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
   p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
   p +(p +4) +(2p +5) = 45
   4p = 36 . . . . . . . . . . . . . subtract 9
   p = 9 . . . . . . . . . . . divide by 4
   d = 9 +4 = 13
   q = 2(9) +5 = 23
The value of the collection is ...
   23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.