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Ghella [55]
3 years ago
8

What’s da answer I can write a poem or tell about picture

Mathematics
1 answer:
dsp733 years ago
4 0
Yes i agree with you
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Please assist me with this problem​
iren [92.7K]

Answer:

b. x + 1

Step-by-step explanation:

x¹⁶ − x¹⁴ = k (x¹⁵ − x¹⁴)

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x² − 1 = k (x − 1)

(x − 1) (x + 1) = k (x − 1)

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3 years ago
The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz
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Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

N = \dfrac{z^2 \cdot p \cdot q}{e^2}

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

N = \dfrac{1.645^2  \times 324}{3^2} = 97.4169

Therefore the appropriate sample size, N ≈ 97 adults.

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