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Wittaler [7]
2 years ago
14

How to take a line in desmos and reflect it over y axis and find equation.

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
7 0

Answer:

Reflecting a function over any axis can be complicated if you do not know the proper way to do it, so I am going to use examples to show you.

If f(x)=x is your normal function, then flipping it across the y-axis would look like f(x)=-x.

Step-by-step explanation:

Placing a - sign before the X will make it flip across the y-axis. After the X, and it flips across the X-axis.

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What is the value of x?<br>​
Helen [10]

10x - 4 + 8x + 3 = 180 - 91 \\ 18x - 1 = 89 \\ 18x = 90 \\ x = 5

5 0
3 years ago
The graph of a linear equation contains the points (3,11) and (-2,1) Which point also lies on the graph
Svet_ta [14]
m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{1 - 11}{-2 - 3} = \frac{-10}{-5} = 2

y - y₁ = m(x - x₁)
y - 11 = 2(x - 3)
y - 11 = 2(x) - 2(3)
y - 11 = 2x - 6
  + 11        + 11
       y = 2x + 5
6 0
3 years ago
Read 2 more answers
Please help me with the domain and range this is Algebra 2
adelina 88 [10]
Domain: The set of all real numbers
We can plug in any x value we want and there aren't any restrictions. There aren't any holes, jumps, gaps, or asymptotes

-------------------------------------------------

Range: Only one value is in the range and it is the value 2. We can write this as {2}. The curly brackets indicate "set". It is possible to have a set of only 1 item inside.

The range is the set of y value outputs. In this case, the output is 2 because we have a horizontal line. No matter what the x input is, the output is always 2. This is known as a constant function. The output is constantly the same.
3 0
3 years ago
How many area codes (abc) would be possible if all three digits could be any vaiue 1-9
kifflom [539]

Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

3 0
3 years ago
Determine the relationship described in each table.<br><br><br> Please help me
SCORPION-xisa [38]
I graphed the given points and based on my graph.

<span> x    y  </span>→ EXPONENTIAL<span><span>
</span> <span> -2 21
</span><span> 1   4
</span><span> 0   1
</span><span> 1   0

</span></span><span> x    y  </span>→ LINEAR<span><span>
</span> <span> -2   6
</span> <span> -1 -2
</span><span> 0   2
</span><span> 1  6
</span></span>
<span> x    y  </span>→ QUADRATIC<span><span>
</span> <span> -2 12
</span> <span> -1 -2
</span><span> 0 -8
</span><span> 1 -6

</span></span><span> <span><span> x   y  </span></span></span>→ EXPONENTIAL<span><span><span>
</span> <span> -2 16
</span> <span> -1  8
</span><span> 0   4
</span><span> 1  2

LINEAR FUNCTIONS always maintain a constant slope. In the above linear function, the slope is 4. 

EXPONENTIAL and QUADRATIC FUNCTIONS have different slope in every point.

Exponential functions can be identified by the immediate increase or decrease in the value of y resulting to a minimal increase or decrease in the value of x. 

Quadratic functions can be identified as such due to the similar points it has after having the vertex. 

</span></span></span>

5 0
3 years ago
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