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Gemiola [76]
2 years ago
15

Can you please tell me what subtotal is?

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
8 0

Answer:

where the problem

Step-by-step explanation:

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The diameter of the attic is 18ft and its height is 18ft. What's is the volume of the space in the attic
Svet_ta [14]
I attached an image with the complete question.

Answer:
volume of attic = 1526.04 ft³

Explanation:
Volume of cone can be calculated using the following rule:
Volume = \frac{1}{3} * area of base * height
Volume = \frac{1}{3} * π * radius² * height
We are given that:
π = 3.14
radius = 18/2 = 9 ft
height = 18 ft

Substitute in the equation to get the volume as follows:
Volume = \frac{1}{3} * 3.14 * (9)^2 * (18) = 1526.04 ft³

Hope this helps :)

5 0
3 years ago
Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
6 0
1 year ago
3.) Identify all integers.<br> a. 725<br> d. 50<br> e. 10.2<br> C. 806
NeTakaya

Answer:

A, B, C

Step-by-step explanation:

An integer is a whole number (so not a fraction)

8 0
3 years ago
Read 2 more answers
A scuba diver is 23 feet below sea level.A second diver is 7 feet closer to the surface. What integer represents the second scub
NeTakaya

Answer:

The integer is -16

Step-by-step explanation:

The first scuba diver is 23 feet below sea level. THe second is 7 feet closer.

23 - 7 = 16. He is still under sea level, so it would be -16

6 0
3 years ago
Please I really need help
ohaa [14]

9514 1404 393

Answer:

  • scale factor: 3
  • rule: (x, y) ⇒ (3x +15, 3y -24)
  • center: (-7.5, 12)

Step-by-step explanation:

The scale factor can be found by comparing the length of CB to the length of RQ.

  B-C = (-2, 8) -(-4, 9) = (2, -1)

  Q-R = (9, 0) -(3, 3) = (6, -3)

The length of RQ is clearly 3 times the length of CB, so the scale factor (k) is ...

  ratio of corresponding differences = 6/2 = -3/-1 = 3 . . . . . scale factor

__

We know that for dilation about a point O, the distance from O is multiplied by the scale factor. For dilation of point B to point Q, this means ...

  k(B -O) = (Q -O)

Solving for Q, we get ...

  Q = kB -kO +O . . . . this is what our dilation rule will look like.

The quantity O-kO can be found by subtracting kB:

  Q -kB = O -kO = O(1 -k)

This is what we need for our dilation rule.

  Q -kB = (9, 0) -3(-2, 8) = (9+6, 0-24) = (15, -24)

So, our dilation rule is ...

  (x, y) ⇒ k(x, y) +(15, -24)

  (x, y) ⇒ (3x +15, 3y -24) . . . . . dilation rule

__

The center of dilation can be found from ...

  (Q -kB)/(1 -k) = O

  O = (15, -24)/(1 -3) = (-7.5, 12)

The center of dilation is (-7.5, 12).

_____

<em>Additional comments</em>

On the graph, the center of dilation can be found by drawing a line through a point and its image. (Points are always dilated along a line through the center of dilation.) The intersection of two such lines is the center of dilation.

On this graph, the center is just above the top edge of the chart, at point (-7.5, 12). You can see this if you carefully draw lines BQ and AP.

You usually have coordinates for two original points and two image points, so finding the scale factor the way we did is not difficult. If you just have one point on the original and the image, the scale factor is found by finding their distances from the center of dilation. Each image point is k times as far as each original point from that center.

7 0
2 years ago
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