The perpendicular bisector of RT is B. SU.
Answer:
The answer is 62.8
Step-by-step explanation:
C=2(3.14)(r)
c=6.28(10)
c=62.8
You are partially correct :) 2^SQR(10) x SQR(10) = 20
The answer is just 20
Answer: Hello your question lacks some details attached below is the complete question
answer:
- Place a compass at point Q ,
-
measure arc PQ
-
Draw an arc with the compass that is equal to PQ
,
- Place the compass at point R
,
- cut through the line to the left of R with the arc in compass,
-
Assume the new points to be P' and R be Q'
, where P' Q' will become the new image of PQ with their end point will be R
Step-by-step explanation:
The steps required to draw an arc intersecting the line that will create a segment with length PQ are ;
Place a compass at point Q , measure arc PQ
Draw an arc with the compass that is equal to PQ
, Place the compass at point R
, cut through the line to the left of R with the arc in compass,
Assume the new points to be P' and R be Q'
, where P' Q' will become the new image of PQ with their end point will be R
Answer:
positive 6
Step-by-step explanation:
you first plug the number gives and you solve it gives you -6, on the following equation there are "| |" that's mean that if is a negative number it change to positive, but if is a positive number the answer remains positive as well.
hope it helps