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Oduvanchick [21]
3 years ago
11

1. Determine the domain and range of the quadratic function shown in the graph and represent the domain

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0
10 daddy chipllllllhsjsjsj
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ABCD is a parallelogram. Find the values of x and y. Solve for the value of z, if z=x−y.
slava [35]

Answer:

C

Step-by-step explanation:

Parallel and opposite sides of a parallelogram are equal. Hence, we can say:

x + 30 = 2x - 10

and

2y-10 = y +10

Solving first one, we get:

x + 30 = 2x - 10

30+10 = x

x = 40

Also

2y - 10 = y + 10

y = 10 + 10

y = 20

Now, z = x - y, so

z = 40 - 20 = 20

Answer C is right.

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3 years ago
What is the slope of the line shown on the graph?
ale4655 [162]
Hi do u want me to give you the answer or give u the formula?

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Which fraction has the same value as 0.6
Zinaida [17]

Using the place value chart we can see that the decimal 0.6 is six tenths, so we can write 0.6 as the fraction \frac{6}{10}. Notice however that \frac{6}{10} is not in lowest terms so we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.

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3 years ago
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Plz help I don’t know the answer
Dahasolnce [82]
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5 0
3 years ago
Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
3 years ago
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