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3 years ago

Extra Points! Solve the equation .

Mathematics

1 answer:

hodyreva [135]3 years ago

3 0

Answer:

r = -0.1125

Step-by-step explanation:

It works well to subtract 0.5 and convert the percentage to a decimal. You can find the sum by hand or using a calculator.

r = -0.5 +0.0025 -0.125 +0.51

r = -0.1125

_____

<em>Comment on the use of a calculator</em>

Many calculators assume that a percentage is to be multiplied by something. If you type this expression into the Google calculator, it will take the % symbol to be an indicator that modulo arithmetic is desired. (It will compute .25 mod -.125 = 0.) So, you need to be aware of how your calculator handles "%". It may be best to do the conversion to decimal before you present the problem to a calculator.

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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

The solutions to the inequality y < to -x+1 sre shaded on the graph. Which point is a solution

Citrus2011 [14]

<h3>Answer: B. (3,-2)</h3>

There are two ways to confirm this is the answer. The first is to note that (3,-2) is on the boundary, so it is part of the solution set. This only works if the boundary line is a solid line (as opposed to a dashed or dotted line).

The second way is to plug (x,y) = (3,-2) into the given inequality to find that

$y \le -x+1\\\\-2 \le -3+1\\\\-2 \le -2$

which is a true statement. So this confirms that (3,-2) is in the solution set of the inequality.

7 0

3 years ago

What is the simplified version of (-3x^3y^2) (5xy^-1)?

GuDViN [60]

Answer:

-15x^4y

Step-by-step explanation:

(-3x^3y^2)(5xy^-1)

-15x^4y^2/y

-15x^4y

3 0

4 years ago

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Write an expression to represent the area

nlexa [21]

Answer:

20(x+15.5)

Step-by-step explanation:

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3 years ago

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Evaluate<br> 5-(2w-8)=6w-9

Brilliant_brown [7]

Step-by-step explanation:

Steps

5−(2w−8)=6w−9

Show Steps

Expand 5−(2w−8): −2w+13

−2w+13=6w−9

Subtract 13 from both sides

−2w+13−13=6w−9−13

Simplify

−2w=6w−22

Subtract 6w from both sides

−2w−6w=6w−22−6w

Simplify

−8w=−22

Divide both sides by −8

−8w

−8 =

−22

−8

Show Steps

Simplify

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5 0

3 years ago