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3 years ago

PLEASE ANSWER THE 3 QUESTIONS IN THE PICTURES BELOW

Mathematics

1 answer:

nexus9112 [7]3 years ago

4 0

1)

the answer is C

2)

The answer is B

3)

The answer is D

Hope this helps :)

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HELPPPPP ASAPPPP

KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :

$h(t)=-16t^2+20t+6$ ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put $\dfrac{dh}{dt}=0$

Now put t = 0.625 in equation (1)

$h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}$

So, the maximum height of the volleyball is 12.25 feet.

5 0

3 years ago

The area of square LMNO is 130 square inches. Find the length of Segment LM.

lakkis [162]

Answer:

11.401754251 or the square root of 130

Step-by-step explanation:

the length squared is the area so you have to do inverse operations and do the square root

4 0

2 years ago

Write the product of -2 and (3 - 5a) as the sum of two factors

NARA [144]

-6 + 10a

-2x3=6 and -2x-5a is 10a

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2 years ago

What is 12 times 135?

ale4655 [162]

the answer for 135 times 12 is 1620

4 0

2 years ago

Read 2 more answers

Remember to check for extraneous solutions

larisa86 [58]

$Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}$

3 0

3 years ago

Read 2 more answers