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mihalych1998 [28]
3 years ago
5

Use set notation to write the members of the following set, or state that the set has no members. Odd numbers between 2 and 82 t

hat are multiples of 9
Mathematics
1 answer:
adell [148]3 years ago
3 0

Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}

The odd multiples of 9, m, in the range 2\le m \le 82 form the set

\{9,27,45,63,81\}

Each member of the set is a term of the arithmetic progression

U_n=18n+9

where the values of n range from 0 to 4, or 0\le n\le 4

Putting these facts together, we get the result

D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}

Learn more about set-builder notation here: brainly.com/question/17238769

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Suppose there are 200 lockers and 200 students. Kayla reasons that since there are 10
Rus_ich [418]

Answer:

Kayla's reasoning is not correct.

Step-by-step explanation:

The locker problem is as follows:

Imagine you are at a school that has student lockers. There are 200 lockers, all shut and unlocked, and 200 students. Suppose the first student goes along the row and opens every locker. The second student then goes along and shuts every other locker beginning with number 2. The third student changes the state of every third locker beginning with number 3. (If the locker is open the student shuts it, and if the locker is closed the student opens it). The fourth student changes the state of every fourth locker beginning with number 4. Imagine that this continues until the 200 students have followed the pattern with the 200 lockers. At the end, which lockers will be open and which will be closed? Why?

Solution:

So from the information we know that the first student goes along the row and opens every locker.

Then the second student shuts every other locker, i.e. locker numbers 2, 4, 6, 8, 10, ..., 196, 198 and 200.

Then the third students changes the state of every third locker, i.e. he/she closes an open locker and opens a closed locker.

So the open lockers are: 1, 5, 6, 12,...

Then the fourth students changes the state of every fourth locker.

So the open lockers are: 1, 4, 5, 6, 8,....

So, on we will observe that the open lockers have a perfect square number such as, 1, 4, 9, 16,....

Consider that the pattern is as follows:

Student 1 opens the locker, Student 2 closes it, Student 3 opens it, person 4 Student and so on.

This is because the square numbers always have an odd number of factors, which leads them to be open at the end.

Take any locker number, 40, for example. Its state (open or closed) is changed for every student whose number in line is a factor of the locker number.

Student      Locker 40 status

     1                    Open

     2                   Close

     4                   Open

     5                   Close

     8                   Open

     10                  Close

    20                  Open

    40                  Close

Like all other lockers numbered with non-square numbers, it ends up closed after all the students have gone through the line because it has an even number of factors.

Consider the locker number 16:

Student      Locker 16 status

     1                    Open

     2                   Close

     4                   Open

     8                   Close

     16                  Open

Thus, we can conclude that all the doors with square numbers on them will remain open because all square numbers have an odd number of factors and the doors with non-square numbers on them will remain close because they have even number of factors.

There will be a total of 14 lockers open.

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169 and 196

So, if there are 10 lockers open in the first 100 lockers there must be only 4 other lockers opened in the next 100.

5 0
3 years ago
Given f(x) = 2x + 1, find the range value if the domain value is 1.75.
MAXImum [283]

Given:

The function is

f(x)=2x+1

To find:

The range value if the domain value is 1.75.

Solution:

Domain is the set of input values and range is the set of output values.

Here, range value if the domain value is 1.75. It means the value of function f(x) at x=1.75.

Substitute x=1.75 in the given function.

f(1.75)=2(1.75)+1

f(1.75)=3.5+1

f(1.75)=4.5

Therefore, the required range value is 4.5.

4 0
3 years ago
HELP 20 PTS!!! Which ordered pair in the form (x, y) is a solution of this equation? (x + 7)y = 10
Vlad [161]

Answer:

x = 3 y = 1

Step-by-step explanation:

3 + 7 = 10

10 x 1 = 10

Have a great day and good luck :)

8 0
3 years ago
here are the ingredients for making fish pie for 5 people. 180g flour,240g fish,80g butter,4 eggs, 180ml milk . Lan makes a fis
kvasek [131]
5p = 80b
3(5p) = (80b)3
15p = 240b

Lan need 240g of butter to make fish pie for 15 people.
8 0
3 years ago
Read 2 more answers
Liev is assembling a coffee table. The diagram below is from the instruction manual and shows the table after the first two legs
elixir [45]

Answer:

The support is 41 inches long.

Step-by-step explanation:

There's two ways we can do this: one with the diagonal formula and one without.

Since we know that Point C is halfway down leg A and that the table legs are 18 inches tall, Point C is 9 inches down leg A. The support, from Point C to Point D, will form a diagonal, the length of which we need to find. We know from the diagram that the width of the table is 24 inches and that its length is 32 inches. We have a height, length, and width for this problem, so let's imagine a rectangular prism, which has all three of those things, instead of a table. The formula for finding a rectangular prism's diagonal is d = \sqrt{l^{2} + w^{2} + h^{2} }. Let's put in those numbers:

d = \sqrt{32^{2} + 24^{2} + 9^{2} } =  41

Therefore, the support is 41 inches long.

--------------------------------------------------------------------------------------------------------------

Another way you can do this is to use the Pythagorean Theorem twice: once to find the diagonal of the tabletop and another time for the support.

24^{2} + 32^{2} = c^{2} \\576 + 1024 = c^2\\1600 = c^2\\\sqrt{1600} = \sqrt{c^2}\\ 40 = c

Now that we know the corner-to-corner distance for the tabletop, we'll use that and the 9 inch distance for Point C to find the distance between C and D:

9^{2} + 40^{2} = c^{2}\\ 81 + 1600 = c^2\\1681 = c^2\\\\sqrt{1681} = \sqrt{c^2} \\41 = c

Again, the support is 41 inches long.

4 0
3 years ago
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