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ziro4ka [17]
3 years ago
6

Determine the probability (as a decimal rounded to the nearest hundredth) of a normal random variable with a mean of three and a

standard deviation of four realizing a value that is strictly greater than 1.9
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

Step-by-step explanation:

On a normal distribution table with z scores of 0 as the mean and the standard deviations going to the right and to the left, 1.9 on the normal curve where 3 is the mean falls at -.275 on the normal curve where 0 is the mean. I used the normal distribution z table for negative values to get that .39165 lies to the left of -.275, which means that 1 - .39165 of the data lies to the right.

The probability that the value is greater than 1.9 is .60835, or as a percentage, 60.835%.

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