Answer: 
Step-by-step explanation:
The midline of the function is

This means that to obtain a maximum of 10, when
reaches it's maximum, 1, 
Answer:
$3.94
Step-by-step explanation:
$30.42 + $9.89 + $5.75 = £46.06
$50.00 - $46.06 = $3.94
(1,6)
This should help for future problems
<span>https://www.mathportal.org/calculators/analytic-geometry/triangle-calculator.php</span>
Answer:
5 units
Step-by-step explanation:
An isosceles triangle is a triangle with two legs that have the same length. The perimeter of a triangle is the sum of the lengths of all sides of the triangle. Now taking this into account, we know that:
2L + B = 14 units
Where:
L is the measure of one leg
B is the measure of the base
Since two legs are the same and the base is 1 less, this means the measure of each leg would be:
B = L -1
Now we have two equations:
2L + B = 14 units
B = L- 1
We plug one equation into the other and make 1 equation:
2L + (L-1) = 14 units
Get rid of the parentheses:
2L + L - 1 = 14
Combine like terms:
3L - 1 = 14
Add 1 to both sides of the equation:
3L - 1 + 1 = 14 + 1
3L = 15
Divide both sides by 3:
3L/3 = 15/3
L = 5
So the length of a leg is 5 units
Let's check!
B = L - 1
B = 5 - 1
B = 4
Then we use that to solve for the perimeter:
2L + B
2(5) + 4
10 + 4 = 14
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"