Question

A jar containing only dimes and quarters contains a total of 54 coins. The value of all the coins in the jar is $9.15. Solve by elimination to find the amount of dimes and quarters that are in the jar.

Answer 1

Answer: the jar contains 29 dimes and 25 quarters.

Step-by-step explanation:

The worth of a dime is 10 cents. Converting to dollars, it becomes

10/100 = $0.1

The worth of a quarters is 25 cents. Converting to dollars, it becomes

25/100 = $0.25

Let x represent the number of dimes contained in the jar.

Let y represent the number of quarters contained in the jar.

A jar containing only dimes and quarters contains a total of 54 coins.. This means that

x + y = 54

The value of all the coins in the jar is $9.15. This means that

0.1x + 0.25y = 9.15 - - - - - - - - - - - 1

Substituting x = 54 - y into equation 1, it becomes

0.1(54 - y) + 0.25y = 9.15

5.4 - 0.1y + 0.25y = 9.15

- 0.1y + 0.25y = 9.15 - 5.4

0.15y = 3.75

y = 3.75/0.15 = 25

x = 54 - y = 54 - 25

x = 29