What size of the angle is being constructed

Helpppp pleaseeeeeeeeeeeeeee

Vesna [10]

Answer:

Find below the calculations of the two areas, each with two methods. The results are:

Upper triangle:

$Area=5000\sqrt{3}units^2$

Lower triangle:

$Area=14,530m^2$

Explanation:

A) Method 1

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

$Area=side_1\times side_2\times sin(\alpha)$

Where, $\alpha$ is the measure of the included angle.

1. Upper triangle:

$side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2$

2. Lower triangle:

$side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2$

B) Method 2

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

$Area=(1/2)\times base\times height$

Use it for both triangles.

3. Upper triangle:

The trigonometric ratio that you can use is:

$sine(\alpha)=opposite\text{ }leg/hypotenuse$

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

$sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units$

$Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2$

3. Lower triangle:

$sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2$

$Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\ Area=14,529.96m^2\approx 14,530m^2$

5 0

3 years ago

75 is what percent of 350

Oduvanchick [21]

Answer=21.4%

75 x
____=___
350 100

cross multiply
350x=7500
divide both sides by 350
x=21.4285714286
round to the nearest tenth
x=21.4%

4 0

3 years ago

Read 2 more answers

What is the distance between the points (4,5) and (10,13) on a coordinate plane?

Readme [11.4K]

The distacne between the points (x1,y1) and (x2,y2) is
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so

$D=\sqrt{(10-4)^2+(13-5)^2}$
$D=\sqrt{(6)^2+(8)^2}$
$D=\sqrt{36+64}$
D=√100
D=10
the distance is 10 units

7 0

3 years ago

A rectangular pool has a sidewalk around it. The pool measures 6 feet by 10 feet and the total area of the pool and sidewalk is

Otrada [13]

Answer:

width of the sidewalk = 1 feet

Step-by-step explanation:

Area of the pool = length × width

Length = 10 feet

Width = 6 feet

Area of the pool = length × width

= 10 feet × 6 feet

= 60 feet²

Area of the pool = 60 feet²

Total area = Area of the pool + Area of sidewalk

96 feet² = 60 feet ² + Area of sidewalk

Area of sidewalk = 96 feet² - 60 feet ²

Area of sidewalk = 36 feet²

Length of pool + sidewalk = 10 + 2x

width of pool + sidewalk = 6 + 2x

( 10 + 2 x ) ( 6 + 2 x ) -60 = 36

60 + 20x + 12x + 4x² - 60 = 36

4x² + 32x - 36 = 0

4x² + 36x - 4x - 36 = 0

4x (x + 9) -4(x + 9) = 0

(4x - 4) (x + 9) = 0

4(x - 1) (x + 9) = 0

(x - 1) = 0 (x + 9) = 0

x = 1 or x = -9

The width of the side walk can't be a negative value

Therefore, width of the sidewalk = 1 feet

7 0

3 years ago

Meteorologists in Texas want to increase the amount of rain delivered by thunderheads by seeding the clouds. Without seeding, th

Dafna11 [192]

Answer:

There is no significant difference in the amount of rain produced when seeding the clouds.

Step-by-step explanation:

Assuming that the amount of rain delivered by thunderheads follows a distribution close to a normal one, we can formulate a hypothesis z-test:

Null Hypothesis

$\bf H_0$ : Average of the amount of rain delivered by thunderheads without seeding the clouds = 300 acrefeet.

Alternative Hypothesis

$\bf H_a$ : Average of the amount of rain delivered by thunderheads by seeding the clouds > 300 acrefeet.

This is a right-tailed test.

Our z-statistic is

$\bf z=\frac{370.4-300}{300.1/\sqrt{30}}=1.2845$

We now compare this value with the z-critical for a 0.05 significance level. This is a value $\bf z^*$ such that the area under the Normal curve to the left of $\bf z^*$ is less than or equal to 0.05

We can find this value with tables, calculators or spreadsheets.

In Excel or OpenOffice Calc use the function

NORMSINV(0.95)

an we obtain a value of

$\bf z^*$ = 1.645

Since 1.2845 is not greater than 1.645 we cannot reject the null, so the conclusion that can be drawn when the significance level is 0.05 is that there is no significant difference in the amount of rain produced when seeding the clouds.

8 0

3 years ago

What size of the angle is being constructed ​

What size of the angle is being constructed