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VladimirAG [237]
3 years ago
5

Anybody else sometimes forget where they are??

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Bro don't play w me I'm chillin w the dinosaurs.

Step-by-step explanation:

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I need help what’s the answerrr
Oliga [24]

The answer is 47. Just keep adding 4.

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3 years ago
Mrs. Walters drove 360 miles of gas on 25 gallons of gas. Mr. Walters drive 480 miles on 32 gallons of gas. A. find the mileage
NikAS [45]
A.360 / 25= 14.4
B. 480 / 32= 15

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3 0
3 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
Find the measure of each angle I’ll mark the brainiest :)
laila [671]

Answer:

9. 70°  10. 90°  11. 110°

Step-by-step explanation:

12. 25°

13. 95°

14. 20°

3 0
3 years ago
Pls awnser thank you maybe
Zanzabum

Answer:

Step-by-step explanation:

..

6 0
3 years ago
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